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Can anyone explain this one? When I run (add-1 zero) it just returns #procedure. I don't understand how this is suppose to be one.

dtmetz
2 years ago

The numbers represent how many times (f) is going to be composed on the value x. So 0 will be just x. 1 will be f(x). 2 will be f(f(x)) and so on.

meowzero
2 years ago

I think I see - essentially just the count on the stack.

dtmetz
2 years ago

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